Given n non-negative integers a1, a2, …, an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container and n is at least 2.

Example:
Input: [1,8,6,2,5,4,8,3,7]
Output: 49
Thoughts
- 设左右两个指针\(l\)和\(r\),从两侧向中间移动,扫描所有有可能大于当前最大值的长方形
- 因为向中间移动肯定会导致底部变短,所以每次移动要选择有可能使得高(high)变长的指针移动
Code(JAVA)
public int maxArea(int[] height) {
int l = 0, r = height.length-1;
int area = 0;
while(l < r){
area = Math.max(area,Math.min(height[l],height[r])*(r-l));
if(height[l] < height[r])
l ++;
else
r --;
}
return area;
}